Thread started by onemanstrash at 02.28.10 - 9:22 pm

Are you good at counting?
how many dribbles

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RE-POST!



-Dexter-
02.28.10 - 9:26 pm

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oh my teacher showed this to us in psychology class.



BoneCrush
02.28.10 - 10:00 pm

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reposssssssssst



mattspeed
02.28.10 - 10:03 pm

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they put a cycling twist on this? that is new from what I saw before



braydon
02.28.10 - 11:09 pm

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oldie but goodie, with a cycling twist!



tfunk408
02.28.10 - 11:22 pm

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repost for the cycling twist. I wish we had ads like this here.



onemanstrash
03.1.10 - 10:23 am

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if asin^2+bcos^2=1 prove that sin^2 equals 1-b/a-b. so far i have 1-b cos^2=sin^2
how do i get a-b?



mechazawa
10.6.10 - 11:11 pm

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***head fizzle*** ***drop to floor***



bentstrider
responding to a comment by mechazawa
10.7.10 - 1:20 am

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asin2+bcos2=1
asin2=1-bcos2

but cos2=1-sin2
so: asin2 = 1-b(1-sin2) = 1-b+bsin2
asin2-bsin2=1-b
(a-b)sin2=1-b
sin2=(1-b)/(a-b)



tfunk408
responding to a comment by mechazawa
10.7.10 - 1:34 am

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Hah, I love that video.



graciela
10.7.10 - 10:37 am

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thanks for the help. i now understand the step that i was obviously missing. b(1-sin^2) = b -bsin^2.



mechazawa
responding to a comment by tfunk408
10.7.10 - 11:29 am

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You guys are killing those of us who have yet to figure out advanced algebraic concepts,

fuckin' Blue Ribbons.



bentstrider
responding to a comment by mechazawa
10.7.10 - 12:55 pm

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